If it's not what You are looking for type in the equation solver your own equation and let us solve it.
k^2-14k+13=0
a = 1; b = -14; c = +13;
Δ = b2-4ac
Δ = -142-4·1·13
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-12}{2*1}=\frac{2}{2} =1 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+12}{2*1}=\frac{26}{2} =13 $
| x+49=121 | | -8/7n=3 | | x=2+.7(40) | | 12*10^2x=29.53 | | 4.9t^2+28t-170=0 | | -4.9t^2+28t-170=0 | | 4.2x=12.6 | | 2m/3m-1/2=3/7 | | X2+y2=900 | | 2/3m-1/2=3/7 | | 7x-17=3x+7 | | 5(2x=3+8)= | | 8x+7-2×+5=4×+12-(×-30) | | -2x-7x=63 | | ?=18x2 | | 4(6x-5)=24x-20 | | 4/7x+1/2=-1/4 | | 4/7x+1/2=-4 | | 3(m+2)-5(m+3)=1 | | 6-(1/6)x=(9/2) | | 10x-12=2(3x+4) | | 99(33x+99)+(x+33)=14 | | (9/2)x+(2/3)=(5/3)+(3x/5) | | -15=-3(a+6) | | 2x2=8-6x | | 120*14*x*91=1330056 | | (n-1)=-2(3+n) | | 2(2x-1)+4x=4x-2+4x=8x-2 | | 9x^2=5-x | | x+18=60 | | u^2–3u–4=0 | | 0=4m^2-21m-18 |